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Electron Dot structure of NaOH KCN CaCO3 NH4Cl



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hello dear students

a very good morning to all of you dear

children today's video is about the

lewis dot structures of some special

molecules

like naoh kcn caco3 and nh4cl

so i am saying these molecules special

because these molecules are having

two different types of bonding they are

having electrovalent

as well as covalent bond okay so let's

start the video

let's take any edge first

so in any way as you can see here that

one metal atom is present

and we know about the metal that metal

completes their octet

by losing their electron okay so we know

that sodium has

2 8 1 means only one electron in

its outermost shell so in order to

complete

its octet it has to donate this electron

okay so sodium will do the same it will

donate this electron to oh species and

this o h

will take this electron and we have to

represent negative charge because of the

acceptation of electron

and from here as electron electron gone

so we have to show the

positive charge okay now because of this

positive

and negative charge they both these

species will attract

uh with each other and will form electro

valent bond

okay so in this way electrovalent bond

is present

in nah now what about the covalent bond

so let's see

so in oh species you can see that oh

oxygen contributes six electron hydrogen

one and we will add one more electron

because of the presence of negative

charge

so we are having total eight electrons

right

now

as we have already used two electrons

okay

so now remaining electrons are six so we

will show these six electron

on oxygen atom as it is more

electronegative

okay and we will put the negative charge

also

so you can see here that oxygen has six

seven eight

and hydrogen has completed its duplet

like

one two it requires only two electrons

so it is having two electron

so in this way covalent bond is present

between oxygen

and hydrogen atom so in totality we can

say

that in this molecule electrovalent as

well as covalent bond is

present so this is the first example of

this category

now let's talk about the second k

c n so again here potassium is a

has metallic character so because of

this it will lose its electron it is

having only

one electron in its outermost shell okay

nineteen two eight eight one

okay so let's see

this electron cn will take and

negative charge will appear here and

here we will show

positive charge okay this is the

electron

which potassium is donating okay now

because of this positive and negative

again electrovalent bond will form

between these two now what about the cn

species

so in cn uh carbon contributes 4

nitrogen 5 and we will add

1 because of negative charge now we are

having

10 electrons

so we have already used two electron

here okay

so now we are having eight electrons so

eight electron we will

represent one two three four five six

seven eight now octet of carbon is not

completed yet

it has only one two three four electrons

okay so

it needs four electrons more so these

four electrons

we will take from these lone pairs of

electron

like this now carbon has six seven

eight nitrogen has six seven eight okay

means octets of both these atoms

completed

so in this way electrovalent and

covalent

both type of bonds are present in this

molecules

again okay now let's talk about the csu3

so in csu3 again calcium has two

electron

in its outer motion okay

20 so 2 8

8 two so it will lose these two electron

and carbonate will take these electron

and we have to show

to a negative charge here or here we

will show two positive

okay so because of this positive

negative electrovalent bond will form

okay now what about the carbonate

so for carbonate

carbon contributes 4 oxygen 3 into 6 and

we will add

2 more electrons because of the 2

negative charge

okay now we are having 4

18 and 2 means 24 electrons

okay in uh out of 24 one two

three four five six six we have already

used

now we are we are having 18 only okay

so these 18 electron we will represent

like this

one two three four five six one two

three four five six six six six eighteen

okay now let's check the octet

so oxygen all the oxygen has completed

their octets like

they are having six seven eight six

seven eight

six seven eight okay now talk we'll talk

about the

carbon so carbon is having one two three

four

five six six electrons only it needs two

more electrons

so these two electron it will take from

oxygen

like this okay now it is also having one

two three four five six seven eight

electrons okay so octet of all the atoms

completed now

and we will show to negative charge also

so you can see here

covalent bond as well as electrovalent

bond

is again present here okay now we will

talk about the

nh4cl so in nh4cl

remember one thing that here no metal

or non-metal is no metal is present

actually this is non-metal but this is

not metal

okay so here no metal is present

still electrovalent bond will present

here

because of the presence of positive and

negative charge

okay this is a very special case of

ionic compound

so here and when you draw the lewis dot

structure of

ammonium chloride remember one thing

that it will break into nh4 positive and

cl negative

when you dissolve this compound in water

okay

so uh when you draw the lewis dot

structure you will use

this form of ammonium chloride okay so

let's draw

as nitrogen is contributed 5 4 into 1

minus 1 okay so we are having

8 electrons so 8 electrons we have

already used 1 2 3 4 5 6 7

8 okay so no remaining electrons are

left

and we have to put positive charge again

as it is having positive charge

now let's talk about the chlorine so in

general chlorine atom has seven

electrons

and here negative charge is also present

so octet of complete

is already completed and because of this

positive and negative charge

they will combine together by

electrovalent bond

okay so in this way electrovalent bond

is present here

and covalent bond is also present in nh4

positive means ammonium ion okay so this

is how

both types of bonding are present in

ammonium chloride

so these are the four examples they are

different type of example

so i hope all the examples are clear to

you thank you