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Naming Bicyclic Compounds



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in this video we're gonna talk about how

to name by cyclic compounds so let's

start with this example how can we name

this molecule the first thing we need to

do is identify the bridgehead carbons

now as we travel from one bridge had a

carbon to another on the left side we're

gonna pass through two carbon atoms on

the right side we're going to pass

through three carbon atoms and at the

top there's one between the two

bridgehead carbons so to name this

compound it's gonna be by cyclo and then

in to set in order three two one

and then how many carbons do we have in

this molecule it's going to be the sum

of these three numbers 3 plus 2 plus 1

which is 6 plus the two bridgehead

carbon atoms so that's eight so octane

so it's by cyclo three two one octane

it's a number it we're gonna start with

a bridgehead carbon and we need to begin

numbering the largest section first so

this is gonna be two three four five and

then the smallest section we're going to

count it last six seven and then eight

so we have a total of eight carbons go

ahead and try these two examples

and also try this one too

so here are the two bridgehead carbon

atoms we have two carbon atoms on the

left side two on the right side and at

the top there's two so this is gonna be

called by Cyclone and then 2 2 2 octane

for the structure on the right here are

the two bridget carbon atoms we have two

carbon atoms on the left two on the

right and one at the top so that's going

to be called by cyclo two to one and two

plus two plus one is five plus the two

bridgehead carbon atoms so that's going

to be seven and so it's gonna be heptane

so we can number it this way carbon 1 2

3 4 5 6 and the last one gets saved for

last because it's the shortest link

here's another two examples that you

could work on

travels to so let's identify the

bridgehead carbons and so we have four

carbon atoms on the left side on the

right side there's two carbon atoms and

in the middle there's no carbon atoms

between the two bridgehead carbons and

so this is going to be called by cyclo

and to send an order four to zero and we

have a total of a carbon atoms so octane

so to number eight we're going to start

with a bridgehead carbon and we're going

to start counting towards the larger

ring and then towards the smaller ring

so there's a total of eight carbons in

that example now for the next one here

are the bridgehead carbons on this side

there's two carbon atoms in the middle

there's one and on the right side this

one so that's going to be called by

cyclo and then in descending order 2 1 1

and we have a total of this is four plus

the two British a carbon so six so

that's gonna be hexane and so it's a

number it we're gonna start with 1 and

then go towards the longest link and

then five and then the one in middle

will be six now let's try one more

example but this time with substituents

feel free to pause the video and try

this problem so let's identify the

bridge had a carbon atoms first on the

left side there are four carbon atoms in

the middle it is zero and on the right

side we can see that there's three

so far we have the name by Cyclone and

then four three zero four plus three is

seven plus the two bridge had a carbon

atoms that's not so no-name now how

should we number this system should we

make this bridge high carbon carbon one

or the one below it as carbon one and

which direction should we begin count in

towards the right or towards the left

we should always count starting with the

larger ring so on the Left we have a six

carbon ring on the right it's a five

carbon ring so we need to number this

ring first so let's try this one let's

start with the bridge like carbon at the

bottom so the bromine atom will be on

carbon 5 and the chlorine atom will be

on carbon eight so that would be a five

bromo and a eight chloro now let's see

what happens if this one is carbon one

the chlorine atom is still on carbonate

but this time the bromine atom is on

carbon 2 so it gives us lower numbers

for the substituents so we're gonna go

with this direction so this is going to

be two bromo - a chloro by cyclo nonny

and we can see we have a total of nine

carbons and so that's how you can name

by cyclic compounds