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all right what I'd like to do is show

you guys how to find X and y-intercept

from an equation 2x minus 5y equals 1

now we give it a graph it's very easy to

remember with y and x intercept R

because we know that the point where it

crosses the y axis that's your

y-intercept ok and we know that it's

going to be at some point 0 comma Y and

our x intercept 3 crosses the x axis and

that is at some point X comma 0 that's

what we call the x-intercept

so it's very easy to remember on a graph

all of its where it crosses each axis

however we come into the problem when we

start doing the equation because here I

don't know what this graph looks like

now we are going to learn later how to

graph this equation but there's a very

simple way we can also do this

algebraically that will help us find the

x and y intercepts and then also learn

how to graph it later

so the one key important thing I want to

that I want to take from this route is

we notice that when the y intercept at

the y intercept X is 0 and at the x

intercept our Y value is 0 because

remember a coordinate point is X comma Y

so here x equals 0 and x intercept is y

0 so I'm going to go ahead and erase

this and then write those two properties

so at the y intercept X is equal 0 and

the x intercept Y is equal

okay so what does it mean 1 1 values

equal to 0 well what we can do is we can

treat this as a function if we say 0 X

is now equal 0 I'm going to now evaluate

this for when X is equal to 0 so I'm

going to plug in 2 times 0 minus 5 times

y equal 1 and then over here I'm going

to say 2x minus 5 times 0 equals 1 so

now looking at these two equations now

what I'm going to do is for this one I'm

going to solve for my variable Y and for

this problem you solved for my variable

X so I know that anything multiplied by

0 is 0 so I'm just going to kind of

cancel them out so never want month with

no minute 5 y equals 1 and over here we

have 2 x equals 1 so now we're just

going to go ahead and simply go ahead

and use our division division property

of equality and since my negative 5 is

multiplied by my Y I'm going to divide

by negative 5 on both sides and here I'm

going to divide by 2 the whole surface

therefore x equals 1/2 and here y equals

negative 1/5

so when go ahead and graph you my two

points if I know that here's my

y-intercept I know that X is zero and my

y value is negative one-fifth

my point is 0 and a 1 bit and my point

here is going to be 1/2 0 so I can go

ahead and plot these two points and they

would be the two intercepts on my

equation alright so that's how you find

the X and y intercept from an equation