welcome in this lecture we would

understand data interpretation will

mainly focus on the tricks and the

techniques to solve data interpretation

problems quickly and the basic idea

behind solving those is mainly

imagination and visualization now most

of the students are struck up when they

see calculations which require really

comprehensive understanding of the

concept so what we'll do today is

understand the type of questions we will

understand what are the basic techniques

we need to analyze or apply for data

interpretation and then work around some

shortcuts so the questions are basically

either in the form of graphs pie charts

line charts tables and really they are

in the form of scatter diagrams

sometimes the questions are also for our

SK slits that means small passages are

given based on which you have to analyze

the data now for all of these kinds of

questions the basic tricks that we need

to understand is the basic quantity

quantitative techniques that we need to

apply our understanding and calculating

the percentages growth rates

approximation unitary method cross

multiplication so these are some of the

basic methods that will apply nearly in

most of the problems which can be solved

through these methods and then this is a

key idea that I usually tell students

what to do so what is important is on a

question on data interpretation usually

you have four to five subsections that

has now when there is sale it's a table

let's say you have a table and you have

to calculate the totals for solving

question a supposedly so those totals

would again be applied to question D and

sometimes it's such that you have to

calculate the questions the totals and

those would be asked in question D would

not be asked in question a but some of

it might be applicable question 2 so

that means if you are solving the

questions

the order you might take a lot of time

so the best idea is to read all the

questions at the first school and see

what on kind of data is required so if

some of the questions require deriving

it from the total start working with the

totals first and then proceed on so this

these are some of their techniques that

will save time in a exam where you are

really running short of time also of

these four or five questions there would

be just one or two question that would

require really time-consuming

calculation so you can either leave

those four end and towards the end or

you could apply techniques for

approximation that we will discuss

further in this video to walk around

quickly for solving such questions now

the first thing that we will understand

in this class is approximation now this

is the key aspect for most of the

questions that are asked based on tables

and the questions that require lengthy

calculation so most of the students are

stuck up when it comes to approximation

we'll learn some quick tricks on do how

to solve the questions of approximation

now when there is a question of

approximation the first thing that is

important is to look at the choices if

the choices are really far away

say for example question 1 if the

choices are 2 5 6 or say 1 that means

the choices are really far off and you

can easily say what would be the answer

however if the choices are close by say

two point five two point four two point

three two point five two point eight and

two point nine what we will do then you

will need to apply bit more of

approximations now how to work around a

question like this you have one seven

eight nine divided by seven 62 and the

exact answer we know is this now when we

apply the technique for approximation

let's say

I approximate this value to 750 now the

main idea is to approximate the values

close to zero so once you have 0 in the

denominator and the numerator it would

be easier to solve so for example if I

reduce twelve-year that makes it 750 and

on the top side list by visualizing this

I can say it's more than double so I do

more than double so I am reducing to

Elvia so double opt when is 24 so I do

more than 24 so let's take a number

which makes the last figure 0 so then I

can say 29 would be the appropriate

number so I can say 1 7 6 0 so this is

one way of approximating then I can

cancel out the zeros and solve it in a

much quicker way another technique that

I usually work around is you take 750

then another 750 you make 1,500 then if

I do another 750 that will make it to 2

5 0 that is to way far away from 1 7 8 9

so what I need to do is let's break this

750 into 3 parts so if I break the 750

into 3 parts I can get 250 250 into 50

now let's simply add 250 so 1500 I add

250 that makes it 1 7 5 0 and that is

very close to 1 7 8 9 and this 250 is

one third of 750 that means I am using 2

times 750 that is 2 and 1/3 of 750 that

is to one third or I can also write it

as 2 point 3 3 and I can put a bar that

says it's a recurring decimal however so

my answer I can say would be close to 2

point 3 and if I look and exactly the

answer comes to be 2 point 3 4 so that

means this is one of the techniques that

you can apply for approximation

I repeat again what you can do here is

there are two ways in which I am

explaining this approximation method the

first is you do 750 you reduce 12 and

then by visualization you can see it's

nearly double of it so you double 12

that's 24

and then since last digit is 9 I make it

29 so as to make the last digit 0 so it

becomes 1 7 6 0 / 750 I can cancel out

the zeros and I can simplify this

fraction to work around that is one

method the another method is I add 750

and 750 that gives me 1,500 now if I add

another 750 it gives me two thousand 250

which is very far from the given

numerator so what I do is I divide this

750 into three equal halves that is 250

each and I add 1 to 50 to it that makes

it one seven five zero now this one

seven five zero is very close to the

numerator that means my answer would be

two times 750 so two and then one third

times of 750 that is to one third that

is really 2 point 3 3 so that is the

first thing now in the second side what

you have is what is the percentage of -

6

sorry 468 of - 1 4 - 8

now if I simply say 100 person makes - 1

4 to 8 so as you can see in most of the

questions what I am preferring is

applying unitary method so that is the

easiest way and the fastest way to work

around so one person would be nearly 2 1

4 so I can say 2 percent would be nearly

4 - 8 and now this is 4 6 8 now if I do

3 percent

what it would be it would become 3 times

of - 1 4 that is 6 3 - that is too far

away now my answer is I already have 428

and and my answer is 468 so my answer

would be closer to 2 rather than closer

to 3 now let's do a half way of it so

when I say halfway off it

that means half of 214 would be hundred

and seven now if I had 107 to 428 that

gives me 535 again this is too far from

the value that we need to derive that

means if I take 2.5 person that also

else very far from my answer that I need

to come on to that means my answer would

be closer to somewhere which would be

2.2 percent nearly because it's far from

this and closer to 2.5 is 335 which is

again a big bigger much bigger number

than this so my answer would be closer

to nearly 2.2 and the exact answer as

you can see is 2.1 so there that is

another technique of approximation that

you use here rather than solving the

complete sum if you solve the complete

sum you can say for 60 divided by 2 1 4

2 8 into 100 and then use all the values

and you say it would be nearly 2.18

percent so rather than doing that you

are trying to simplify it because if you

put the decimal place here ignore the

last digit since they are smaller than

point five you take 214 double 214 that

is 2 428 and you are going you need to

go to close to 468 so that means you

will go somewhere around 2.2 percent as

you can see here we have calculated 3

percent and 2.5 percent for better

understanding and these type of

questions when you solve once or twice

you will have a kind of good

visualization to get closer to

approximations much quicker so in the

first round you might calculate 3

percent but in the second round you

would have an intuition that if I do

- 1 4 into 3 this digit would be 6 and

this if this is 6 this is very far from

this so that my answer can never be

towards 3 so my answer would be closer

to 2 in all possible cases so these are

the way you need to do approximations

for quicker understanding now when it

comes to fraction I usually recommend

don't solve the fractions keep the

fractions as it is until necessary so if

it is necessary if the answer is given

only in decimals then definitely go

ahead and solve the fractions otherwise

there is no need to solve the fractions

now let's say the blue bar denotes the

wheat production and the pink bar

denotes the rice production now in a

which here for the week production

highest now whenever a question like

this is asked what is what you have to

do is you have to do the current year -

the base year divided by the base here

in 200 and this is another standard

formula that you must remember for all

data interpretation questions you might

have come along with binomial problems

and binomial equations which help you

solve the growth rate problems but don't

go into that detail you can simply solve

the questions with a simple formula that

is current here - base here divided by

base here in 200 now if you remember

this formula and you try to apply it

universally now what would happen here

let's calculate it for 2006 what would

happen wheat production is 50 55 60 and

65 so let's say for 2006 it would be 55

- 50/50 in 200 for 2007 it would become

60 - 55 divided by 55 in 204 2008 it

would become 65 - 65 - 60 divided by 60

in 200 now if I simplify there is

it would be five by 50 it would be five

by 55 and it would be five by 60 again

simplifying 1 by 10 1 by 11 and 1 my 12

so I can say the highest production

would be in year 2006 why because if you

have higher numerators

sorry higher denominators the fraction

would decrease and it would be lower

than the answer because if I simply say

1 by 2 or 1 by 3 I can say 1 by 2 is

nearly 50% and 1 by 3 is nearly 33% that

means 1 by 2 is bigger so if you are

numerator and denominator is a smaller

your answer is bigger so if your

denominator is smaller you will have a

bigger answer and therefore highest

value of production would be in the year

2006 similarly if it asks about rice

production and which here would have the

lowest rice production you will again do

the same thing current here - base year

back base here in 200 you will do it for

all and let's say you come up with the

similar answers so you would have for

the last one you would have 5 by 65 into

100 and that 5 by 65 would be the lowest

fraction because in this case you would

have 5 by 65 in this case you would have

5 by 60 in this case you would have 5 by

55 so these would be the three ones for

the rice and then you can say this would

be the lowest among the 3 so here 2008

would have lowest increase in the rice

production that could be visualized now

the next question is sometimes there is

question that is asked to calculate

averages now when you need to calculate

the average there is an interesting

thing

understand us you must look into the

figures and see if they are close to one

another

so for example let's see in this graph

you have all the figures that start with

seven eight zero zero now if I take away

seven eight zero zero I work around the

remaining ones so you have fourteen here

you have twenty nine then you have one

zero eight then you will have addition

of twenty two and finally addition of

Sun finally addition of 120 that means

you will add all the remaining values

except 7 7 800 and so when you add all

these value you get an answer of 293 now

this to 93 is divided among five so 293

divided by five I can simply say five

times or 25 and 40 over so you would

have 8.30 that is 658 point 6 now that's

58.6 I can add on to this therefore the

average of all these values would be

seven eight five eight point six so

that's a simpler way to calculate the

averages rather than going into the

details of each and every thing adding

all the values together but you can take

aside s take the common values out and

then add the remaining values or when

you total out the remaining values take

a average of the remaining values and

add that value to the base value that

you had separated in this starting so

that is how you work around quickly with

the averages now the next thing is pie

diagram now this is a main area where

most of the students are struck up the

simplest thing I would say here is you

have to remember two things first of all

a circle makes 360 degrees that is a

basic key and once you know that circle

makes 360 degree you can turn each an

empty problem now what is given here is

the total C is this 6 lakhs and if it is

asked what would be the sale of cement

how would you calculate this when I say

total

Schlag I can say 360 degrees give you a

sale of six labs so one degree would

give you sale of 367 six by 360 so 72

degrees would give you a sale of 6 by

360 into 72 36 10 2 and then you would

have 12 by 10 that is 1 point 2 so I can

say the sale of cement would be 1 point

2 lots now this is again a simple

unitary method that you need to apply

when you are given with degrees now

another interesting question would be

what would be the percentage of sale if

I take supervisors timbers and Labour's

together now if I have supervisors

timbers and labor together I don't know

what is the degree for timber so first

of all I need to calculate that so I

will add up all the remaining degrees

and subtract that from 360 so that will

give me the answer for timbers is 36

degree now it is given that the sale of

these three together would account for

what percentage of the total that means

54 plus 36 plus 90 so it gives you 54

plus 36 is 19 90 plus 90 is 180 now this

180 out of 360 accounts for what

percentage so I can see it would simply

account for 54 percent of the total and

at that graph is given on to the scale

you can simply see here this line

denotes 50 percent so 5050 this line

denotes the base the graph into the pie

chart into half so you have 50 percent

on that side and these three would again

make up 50 percent so that is how you

solve problems like these for pie graph

so this is the first example for pie

diagram where you are given degrees the

next case we will take is a bit

complicated and you must understand this

carefully now to solve problems like

this there are n number of my

given an N number of books that you can

refer but what will work around is the

simplest of all what is given here is

you are given the total weight of the

sweets that are available at a sweet

shop that is the total weight is 250 kgs

and you are given the proportion of the

weights for each of these you are given

the total cost of the sweets which is 2

5 4 5 0 and you are given the individual

percentage of the cost now if you are

given to calculate the cost of 5 kg of

milk cake how can you do that now the

first and the foremost thing that you

need to understand here is you have to

see if the ratio or the proportion of

weight and the proportion of cost is

saying that you know you don't need to

go further into the details you can

simply solve it with one step let's say

we'll do it for the milk cake first

because it's 2 percent in both the cases

so this makes the question simpler now

we will work around for milk cake and

you are asked to find out the cost of 5

kg of milk cake how you can do that the

total weight is 250 kg now one percent

would make 2.5 kgs and 2 percent would

make 5 kgs now if I know

the total weight is 250 and the total

cost is 2 5 so 2 50 kgs VRU a cost of 2

5 4 5 0 so 5 kgs would be are you a cost

of 2 5 4 5 0 divided by 25 into 5 so

that's one way of solving it another way

of solving it is since the total cost us

to 54.5 for 1 percent it would be 2 54.5

so for 2 percent milk cake it would be

double of this so 250 and 250 is 500 4

point 9

four point five plus four point five is

nine so 500 plus 9 is 5 0 9 again the

shortcut to solve this so I broke this

into 250 plus 4.5 I double this and I

double this individually so this becomes

500 and this becomes 9 now I add this so

it is 5 0 9 now so 2 percent would have

a direct cost of rupees 509 and if I

calculate this I would again get rupees

509 as the answer so this was a very

simple method to solve the problem when

you have equal proportions in the cost

and equal proportions in the weight that

is given now let's complicate this

question further in the next set what is

asked us is cost of five kg of Calaca

now when you are asked about Caloocan

let's look into the weight by weight

Caloocan is 10% and by cost it is 17% so

solution for this won't be as simpler as

we did it for milk cake now let's move

on to solving this section now for 2 50

kgs a hundred percent make 250 cases so

10 percent of the colic on would make 25

kgs that is the first thing you can

solve here now remember what we did

earlier in the fractions don't solve

fractions until necessary so keep

prolonging the factions till the time

they can go now here 10% of the colorant

makes 25 kg and so what we'll do is

we'll first find out for 25 kg how much

is the cost and then we'll move around

for 5 kg what would be the cost now as I

said 17 percent is Caloocan now 1

percent would be 250 4.45 so 17% would

be 250 4.45 into 70 and this makes up

how much Calaca that is 25 kgs in

Pelican so 1 kg

would be 250 4.45 into 17/20 5 & 5 kgs

would be into 5 Nasim now as I said if

you keep the fractions as it is until

end it would be easier to solve rather

than if you multiply this first and you

get a big number and then you again

start dividing it would create whole lot

of mess now you would have 1 & 5 & 5

fives are twenty five then zero and then

you would have 40 that is eight nine the

fifty point eight nine into seventeen

would be the answer now if we simply

calculate 17 fives up would be 85 so it

would be close to somewhere 850 because

it is 50 and since it's 51 now another

thing I can do here is if I add 17 here

it would be 8 6 7 so my answer would be

definitely less than 867 so if I have

various choices I can say my answer

would be less than 867 but more than but

way more than 850 so since it is fifty

point eight nine so I need not to

calculate it exactly if the choices are

far about I can say simply what would be

the answer however the exact answer here

would come in as six eight sixty five

point three so this would be the cost of

five kg of Calaca so I hope you are

designed the difference when you have

the same weight and cost ratio that is

given as we did in the case of milk cake

however if there is a different weight

and cost ratio that is given as in the

case of Caloocan so we need to calculate

it a step further so these are some of

the data interpretation questions on the

various tricks to solve the data

interpretation questions we might work

around more questions on data pretty

entertaining if required

you can leave any douses comment below

the video have a good day